Identify A, B and C in the following reactions : (Comptt. Penta amine carbonato chromium(II) chloride. Answer: (iii) A coupling reaction (Delhi 2009) Delhi, Comptt. C6H5NH2, (C2H5)2NH, C2H5NH2 (Delhi 2014) Answer the following: What is the minimum number of carbon atoms in (a) a branched alkane (b) cyclo-alkane? Question 12.4 Give the IUPAC names of the following compounds: (a) (b) (c) (d) (e) (f) Cl2CHCH2OH Class XI Organic Chemistry : Some Basic Principles and Techniques Page 361 1 See answer BrainlyHelper is waiting for your help. Nomenclature and Structure. (Comptt. (a) Aniline to p-hydroxyazobenzene. Answer: Question 65. Since a stronger base has a lower pKb value therefore basic strength order. (i) Hoffmann-bromamide degradation reaction Write the chemical equations involved in the following reactions: (All India 2016) (ii) Benzene to aniline (Comptt. Basicity order (due to stability of ammonium cation) Answer: Question 18. LEARNING APP; ANSWR; CODR; XPLOR; SCHOOL OS; STAR; answr. (iii) Due to presence of two H-atoms on N-atom of primary amines, they undergo extensive intermolecular H-bonding while tertiary amines due to the absence of a H-atom on the N-atom, do not undergo H- bonding. Delhi 2012) C6H5NH2 < (C2H5)2NH < C2H5NH, Question 13. Question 5. Question 44. Answer: (i) Nitrobenzene into aniline Question 48. (iii) Because of nitration in an acidic medium, aniline gets protonated to give anilinium ion which is indirecting. Aniline, p-nitroaniline and p-toluidine Physics. Answer: (Delhi 2010) (i) Ethylamine and aniline : Hydrocarbons. Give the chemical tests to distinguish between the following pairs of compounds : (i) Hofmann’s bromamide reaction : When amide is treated with bromide in alkaline solution, an amide yields an amine containing one carbon less than the starting amide. 1 Answer. (All India 2011) Diazotization. Give the structures of A, B and C in the following reactions : (Delhi 2014) Question 6. … Give reasons : Question 27. NCERT RD Sharma Cengage KC Sinha. (b) Arrange the following in the increasing order of their basic character in an aqueous solution : Question 51. Give IUPAC name of the compound given below. CHAPTER 12 Give the IUPAC name for each of the following compound Identify which ones are alcohols and classify them as and indicate family group 1) CH-CH:-SH он 3) CH-C-CH2-CH CHs 2) CH-CH-CH-CH2-011 CH 4) CH- O-CH2-CH:-CH 5) CHs-CH:-O-CH CH3-CH2 10 6) CH-CH-CH:-CH:- C-H 7) 8) CH-CH-O-CH:-CH CH-CH-CH2-C-CH он 9 What would be the IUPAC name for the followingCH CH(CHs)CH CH:OH A) … Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 … Write the main products of following reactions: (All India 2013) (b) Ethanoyl chloride to Ethanenitrile. (ii) Arrange the following compounds in a decreasing order of pKb values : Give the IUPAC names of the following compounds: CH 3 CH(Cl)CH(Br)CH 3. (i) Increasing order of basic strength An aromatic compound ‘A’ on treatment with aqueous ammonia and heating forms compound ‘B’ which on heating with Br2 and KOH forms a compound ‘C’ of molecular formula C6H7N. 1st compound: 2nd co Write structures of the following compounds: 2-chloro-3-methylpentane. (b) IUPAC name : Phenyl acetamide, Question 30. (All India 2014) 1780 Views. HCl) at 273-278 K followed by treatment with an alkaline solution of 2-naphthol when a brilliant yellow, orange or red coloured dye is obtained. (Comptt. N-Ethyl-N-methylethanamine, Question 21. Write major product(s) in the following reactions : (Comptt. C2H5NH2, C2H5OH, (CH3)3N Delhi 2015) Consequently, aniline does not undergo Freidel Craft reaction. Give the chemical tests to distinguish between the following pairs of compounds : (i) Methylamine and Dimethylamine Answer: Question 56. Haloalkanes and Haloarenes. Submit Request Answer Problem 12.20 Give The IUPAC Name For Each Of The Following: Part Spell Out The Full Name Of The Compound. Cloudflare Ray ID: 62615a798b1e1a05 2-bromo-3-chlorobutane. (a) Sandmeyer’s reaction (i) Nitrobenzene into aniline. Illustrate the following reactions : (i) Aniline being a Lewis base reacts with Lewis acid AlCl3 to form a salt. This reaction is known as coupling reaction. HCl) at 273-278 K followed by treatment with an alkaline solution of 2-naphthol when a brilliant yellow, orange or red coloured dye is obtained. (i) Due to the strong activating effect of the NH2 group, aromatic amines undergo electrophilic substitution reactions readily than benzene. Submit Request Answer Part B CH3-CH2-CH2-C-CH; Spell Out The Full Name Of The Compound. In order to give compounds a name, certain rules must be followed. Question 16. Complete the following chemical equations: (Delhi 2011) As a result, the (ii) C2H5NH2 + C6H5SO2Cl → (i) Ethyl amine and Aniline (b) Methylamine in aqueous medium gives reddish-brown precipitate with FeCl3. B. H3C NH2 CH3—NH2 has higher boiling point than (CH3)3N. Biology. (a) Write the structures of main products when benzene diazonium chloride reacts with the following reagents : (iii) Aniline to benzyl alcohol. Answer: According to IUPAC system (Unit 12, Class XI), the name of an alcohol is derived from the name of the alkane from which the alcohol is derived, by substituting ‘ e ’ of alkane with the suffix ‘ ol ’. Question 37. All India 2017) Answer: Question 49. Class 10 Class 12. Question 36. (i) Nitrobenzene to benzoic acid. Answer: Question 52. Answer: C6H5NH2, C6H5 N(CH3)2, (C2H5)2NH and CH3NH2 Give the iupac name of the following compound:- C6H6=C=O Please is urgent!!!. All India 2015) (i) Methylamine and Dimethylamine : Give reasons : Delhi 2014) We have provided Coordination Compounds Class 12 Chemistry MCQs Questions with Answers to help students understand the concept very well. (ii) In (CH3)N there is maximum steric hindrance and least solvation but in (CH3)2NH the solvation is more and the steric hindrance is less than in (CH3)3NH; although + I effect is less, since there are two methyl groups; di-methyl amine is still a stronger base than tri-methyl. Thanks! The IUPAC system of nomenclature is a set of logical rules framed which are mainly aimed at giving an unambiguous name to an organic compound. Write IUPAC name of following compounds. H2C=CH—H2C—NH2. Question 39. (i) In an increasing order of basic strength : 0 votes . Hence aniline is weaker base than cyclohexylamine. Can you explain this answer? Answer: Question 74. Answer: Chemistry. 48. Out of CH3—NH2 and (CH3)3N, which one has higher boiling point? As a result, N of aniline acquires positive charge and hence it acts as a strong deactivating group for electrophilic substitution reaction. (c) Although —NH2 is o/p directing group, yet aniline on nitration gives a significant amount of m-nitroaniline. Question 67. Give a chemical test to distinguish between each of the following pairs of compounds : State reasons for the following : Switch; Flag; Bookmark; Write structures of the following compounds: 1-chloro-4-ethylcyclohexane 1-chloro-4-ethylcyclohexane. Join / Login. Complete the following reaction equations : ... Give the `IUPAC` name of the following compound. Switch; Flag; Bookmark; What are the necessary conditions for any system to be aromatic? (a) Aniline is a weaker base than cyclohexyl amine. Arrange the following compounds in an increasing order of their solubility in water : C6H5NH2, (C2H5)2NH, C2HSNH2 (Delhi & All India 2011) Question 20. (b) How would you convert (a) In aniline, the lone pair of electrons on the N-atom is delocalised over the benzene ring. (i) Aniline does not give Friedel-Crafts reaction. (i) pKb value for aniline is more than that for methylamine. Ethylamine (being an aliphatic primary amine) gives a positive carbylamine test, but dimethylamine does not. Answer: Answer: (CH3)2 NH > CH3NH2 > (CH3)3 N > NH3, Question 3. How would you account for the following : (All India 2016) Answer: Question 9. Answer: Complete the following reaction equations: (All India 2009) Delhi 2012) (C2H5)2NH > C2H5NH2 > C6H5NHCH3 > C6H5NH2. Chemistry . All India 2012) (ii) Aniline and Benzylamine (All India 2010) Answer: Explaination: l-Phenylpropan-2-ol. (b) Ethanamide is a weaker base than ethanamine. NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless. Question 2. IUPAC name: N, N Dimethylamine. (iii) pKb of methylamine is less than that of aniline. Ask questions, doubts, problems and we will help you. Answer: Question 26. Give the IUPAC name of the following compounds (a) CH 3 CH 2 CH 2 OH. As a result, N of aniline acquires positive charge and hence it acts as a strong deactivating group for electrophilic substitution reaction. For example : Question 42. Write the IUPAC name of View solution. 757 Views. Describe the following giving the relevant chemical equation in each case : (b) Coupling reaction (Comptt. Answer: Question 53. To understand the name you need to take the name to pieces. Answer: ← Prev Question Next Question → Related questions 0 votes. Question 38. Answer: Question 19. Write the IUPAC name for [Cr(NH 3) 5 CO 3]Cl. 12th. Answer: Answer: C6H5COOH. Answer: Arrange the following compounds in increasing order of solubility in water : • (i) Aniline to nitrobenzene (ii) Aniline to iodobenzene (Delhi 2011) Write the structure of the molecule of a compound whose IUPAC name is 1- phenylpropan-2-ol. View solution. (b) In ethanamide the lone pair of electron of N-atom is not available due to resonance structure Coordination Compounds. Delhi 2016) Question 57. Answer: (CH3)3 < C2H5NH2 < C2H2OH. Also write chemical equations of the reaction involved. Question 62. Likewise, given a IUPAC name, one should be able to write a structural formula. (i) C6H5N2Cl + H3PO2 + H2O → Write chemical equations for the following conversions : The oxidation state of Cs in this compound is +3. This reaction is used to distinguish primary amines from 2° and 3° amines as it is only given by 1° amines with the production of a very bad smelling organic compound. Get the detailed answer: Give IUPAC names for the following compounds:I just need Part B! (i) Br2 water (ii) HCI (iii) (CH3CO)2O/pyridine (i) Ethylamine and Aniline This reaction is Sandmeyer’s reaction. this question is simply naming of organic compounds using the pack rules. (a) Gabriel phthalimide synthesis : It is used to prepare 1° amine (Primary amine). Consequently, aniline does not undergo Freidel Craft reaction. Explain the following reactions : Please enable Cookies and reload the page. electron density on the nitrogen decreases. Give reasons: Account for the following: (ii) Carbylamine reaction. Delhi 2014) (a) Electrophilic susbstitution in case of aromatic amines takes place more readily than benzene. Give the structure of A, B and C in the following reactions : (Delhi 2013) The IUPAC name of the compound `CH_(3)CONH(Br)` is. Complete the following reaction equations : (All India 2012) (i) Aniline does not undergo Friedal-Crafts reaction. Give chemical tests to distinguish between the following pairs of compounds : Answer: (i) CH3CH2Cl to CH3CH2CH2NH2 (ii) CH3NH2 is more basic than C6H5NH2. (iii) Primary amines have higher boiling points than tertiary amines. (CH3)2 NH > CH3NH2 > (CH3)3 N > NH3. Question 58. By Carbylamine test: Methylamine being a primary amine gives this test but Dimethylamine being a secondary amine does not. asked Jan 11, 2019 in Chemistry by kajalk ( 77.7k points) alcohols phenols and ethers (ii) Decreasing order of pKb values Delhi 2014) Answer: Get the detailed answer: 1. (iii) Due to more steric hindrance in (CH3)3N it is less basic than (CH3)2NH. Give the IUPAC name of H2N — CH2—CH2—CH = CH2. CH3NHCH(CH3)2 Sandmeyer’s reaction: The substitution of diazo group of benzene diazonium chloride by Chloro, Bromo and Cyano group with the help of solution of CuCl dissolved in HCl, CuBr/HBr and CuCN/KCN respectively is known as Sandmeyer’s reaction. All India 2012) (i) Due to presence of two H-atoms on N-atom of primary amines, they undergo extensive intermolecular H-bonding while tertiary amines due to the absence of a H-atom on the N-atom, do not undergo H- bonding. As a result, primary amines have higher boiling points than 3° amines. Answer: Identify A and B in each of the following processes : (All India 20100 (i) Higher the pKb value, lower will be the basicity therefore aniline is less basic than methylamine because the (i) Primary amines (R-NH2) have higher boiling point than tertiary amines (R3N). Give the correct IUPAC name or IUPAC accepted common name for the following compounds. All India 2013) Root word Prop. Answer: Explaination: 2, 2-Dimethyl propan-l-ol. The conversion of primary aromatic amines into diazonium salts is known as (All India 2014) (a) Sandmeyer’s reaction : Aniline reacts with NaNO2 in HCl at 273 – 278 K giving diazonium salt which further reacts with cuprous chloride/bromide to give chloro or bromo benzene. Answer: A. (ii) Hofmann’s bromamide reaction (All India 2012) (c) Aniline and Benzylamine can be distinguished by the Nitrous acid test. Books. Write IUPAC name of the following compound: (CH 3 CH 2) 2 NCH 3 (Delhi 2017) Answer: N-Ethyl-N-methylethanamine. Before starting the IUPAC rules, lets see an example of organic compound and it’s IUPAC name. All India 2016) View solution. (ii) Aniline being a Lewis base reacts with Lewis acid AlCl3 to form a salt. lone pair of electrons on nitrogen atom gets delocalized over the benzene ring are unavailable for protonation due to resonance in aniline which is absent in case of alkylamine. (i) Ethylamine and aniline : An aromatic compound ‘A’ of molecular formula C7H6O3 undergoes a series of reactions as shown below. Arrange the following in increasing order of basic strength : Add your answer and earn points. (i) Acetylation of aniline reduces its activation effect because acetyl group being electron withdrawing group attracts the lone pair of electrons of the N-atom towards carboxyl group and the lone pair of electrons on N is less available for donation to benzene ring by resonance. As a result, primary amines have higher boiling points than 3° amines. Check the below NCERT MCQ Questions for Class 12 Chemistry Chapter 9 Coordination Compounds with Answers Pdf free download. (a) Explain why an alkylamine is more basic than ammonia? (b) C2H5NH2 < (C3H5)3N < (C2H5)2NH Your IP: 45.119.80.112 Answer: C6H5—NH2 and C6H5—NH—CH3 (All India 2015) Question 35. (b) Ethylamine and dimethylamine can be distinguished by the carbylamine test. But aromatic primary amines cannot be prepared by this method because aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide. (a) Alcohols: The common name of an alcohol is derived from the common name of the alkyl group and adding the word alcohol to it. C6H5NH2 < C6H5NHCH3 < C6H5CH2NH2, Question 14. (i) Hoffmann’s bromamide reaction : In this reaction, migration of an alkyl or aryl group takes place from carbonyl carbon of the amide to the nitrogen atom. How may methyl bromide be preferentially converted to methyl isocyanide? (ii) Ethylamine is soluble in water whereas aniline is not soluble in water. • Question 1. Answer: Answer: Write the IUPAC name of the given compound: (Delhi 2016) Due to electron releasing inductive effect (+1) of alkyl group, the electron density on the nitrogen atom increases and thus, it can donate the lone pair of electrons more easily than ammonia. Answer: Structure of n-methylethanamine : Number of C – atoms in the longest chain is 3. It also enables every compound to have a unique name, which is not possible with the common names used (for example in industry). Question 25. Answer: View solution. The carbon atom to which –OH group is attached is numbered as C 1 followed by other carbon atoms numbering. Answer: Question 63. Give reasons for the following: (c) By Hinsberg test, secondary amines or (CH3)3NH shows precipitate formation which is insoluble in KOH. I find it helpful to draw the entire structure rather than just using the shorthand technique. An aromatic compound JA’ of molecular formula C7H27ON undergoes a series of reactions as shown below. Aniline, p-Nitroaniline and p-Toluidine (a) Gabriel Phthalimide reaction Gattermann Koch reaction : Diazonium salt reacts with hydrogen halide in presence of copper powder giving haloarene. (ii) Aniline does not undergo Friedel – Crafts reaction. (ii) In a decreasing order of basic strength : (ii) Gatterman reaction: When benzene or its derivative is treated with carbon monoxide and hydrogen chloride in the presence of anhydrous aluminium chloride or cuprous chloride, it gives benzaldehyde or substituted benzaldehyde. Hence Aniline has high pKb molecule i.e., methylamine has less pKb molecule. Answer: IUPAC name : N, N-Dimethylbutanamine. Question 50. (b) Because the primary amine formed by ammonolysis itself acts as a nucleophile and produces further 2° and 3° alkyl amine. (i) Electrophilic substitution in aromatic amines takes place more readily than benzene. Answer: 2-Chloro-5-hydroxy hexane. Question 41. IUPAC name : But-3-ene-1-amine, Question 4. Answer: Question 70. Write the structures A, B and C in the following : (Delhi 2016) Benzylamine reacts with HNO2 to form a diazonium salt which being unstable even at low temperature, decomposes with evolution of N2 gas. Question 31. Give a chemical test to distinguish between ethylamine and aniline. (ii) Ethylamine is soluble in water due to its capability to form Fl-bonds with water while aniline is insoluble in water due to larger hydrocarbon part which tends to retard the formation of H-bonds. All India 2014) Therefore the amine so formed has one carbon atom less than that of amide. This reaction is known as coupling reaction. Click hereto get an answer to your question ️ Give IUPAC name of the compound given below. Question 40. Write the products A and B in the following : (Comptt. (a) Write the structures of main products when aniline reacts with the following reagents : Question 24. Answer: Reduction reaction. Delhi 2017) (ii) Aniline and N-methylaniline C6H5NH2, C6H5NHCH3, C6H5N(CH3)2 (Delhi 2014) Answer: Answer: Question 8. Answer: (ii) C6H5NH2 + Br2 (aq) → Answer: Explaination: Hex-4-en-3-ol. It does not react with tertiary amines. Delhi 2013) But in benzene there is no delocalisation of electron at any position and hence electrophilic substitution in case of aromatic amines takes place more readily than benzene. Answer: Question: Problem 12.20 Give The IUPAC Name For Each Of The Following: Part A CH,–CH2-CH-CH2-C-H Spell Out The Full Name Of The Compound. Suffix – ol. When glucose is treated with bromine water it forms gluconic acid. (c) Give a simple chemical test to distinguish between the following pair of compounds : (i) Arrange the following compounds in an increasing order of basic strength : If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. In the following cases rearrange the compounds as directed : (Delhi 2010) Ar – N = N – Ar. Question 21. Give the IUPAC name of the following compound : (Delhi 2009) Answer: IUPAC name : 2-Bromo-3-methyl-but-2-ene-1-ol. Answer: Question 61. 2-Hydroxy-5 … Write the structures and IUPAC names of compounds A, B and C. (Comptt. Identify A, B and C in the following reactions : (Comptt. Write the IUPAC … Answer: Give two examples of each. (iii) C2H5NH2 + HNO2 → Answer: Question 71. (ii) CH3NH2 is more basic than aniline due to availability of lone pair of electrons for donation while in aniline lone pair of electrons on the nitrogen atom is delocalised over benzene ring and thus unavailable for donation. View solution. C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2 (b) Coupling reaction : Arene diazonium salts react with highly reactive aromatic compounds such as phenols and amines to form brightly coloured azo compounds. Answer: Write the IUPAC name of the following compound: (Comptt. Maths. (8 points, 2 each) â -OH A. Give the `IUPAC` name of the following compound. All India 2012) NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless. (i) C6H5Cl + CH3COCl → By Carbylamine test : Aniline is a 1° aromatic amine while N-methylaniline is a secondary aromatic amine. Question 46. All India 2013) IUPAC name of the following compound is ? MCQ Questions for Class 12 Chemistry with Answers were prepared based on the latest exam pattern. (iii) A coupling reaction : Arene diazonium salts react with highly reactive aromatic compounds such as phenols and amines to form brightly coloured azo compounds. (i) Hofmann’s bromamide reaction How are the following conversions carried out : All India 2017) Best answer. (i) Aniline being a Lewis base reacts with Lewis acid AlCl3 to form a salt. Write the structures of A, B, C, D and E in the following reactions : (All India 2015) electrons on N is less available for donation to benzene ring by resonance. Carboxylic acid chloride group If a given organic compound contains carboxylic acid chloride group (-COCl), then ‘e’ is removed from the end of the corresponding alkane name and add ‘oyl chloride’. C6H5NH2 < (C2H5)2NH < C22H5NH2. (a) Acetylation of aniline reduces its activation effect.